(2x^2-5x+7)(1-x^2)=0

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Solution for (2x^2-5x+7)(1-x^2)=0 equation:


Simplifying
(2x2 + -5x + 7)(1 + -1x2) = 0

Reorder the terms:
(7 + -5x + 2x2)(1 + -1x2) = 0

Multiply (7 + -5x + 2x2) * (1 + -1x2)
(7(1 + -1x2) + -5x * (1 + -1x2) + 2x2 * (1 + -1x2)) = 0
((1 * 7 + -1x2 * 7) + -5x * (1 + -1x2) + 2x2 * (1 + -1x2)) = 0
((7 + -7x2) + -5x * (1 + -1x2) + 2x2 * (1 + -1x2)) = 0
(7 + -7x2 + (1 * -5x + -1x2 * -5x) + 2x2 * (1 + -1x2)) = 0
(7 + -7x2 + (-5x + 5x3) + 2x2 * (1 + -1x2)) = 0
(7 + -7x2 + -5x + 5x3 + (1 * 2x2 + -1x2 * 2x2)) = 0
(7 + -7x2 + -5x + 5x3 + (2x2 + -2x4)) = 0

Reorder the terms:
(7 + -5x + -7x2 + 2x2 + 5x3 + -2x4) = 0

Combine like terms: -7x2 + 2x2 = -5x2
(7 + -5x + -5x2 + 5x3 + -2x4) = 0

Solving
7 + -5x + -5x2 + 5x3 + -2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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